What is the inverse of f(x)=\sqrt[3]{(x^2+1)}-5 ?

The inverse of f(x)=\sqrt[3]{(x^2+1)}-5 is sqrt(x^3+15x^2+75x+124),-sqrt(x^3+15x^2+75x+124)

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inverse of f(x)=\sqrt[3]{(x^2+1)}-5

inverse

x^{3} + 15 x^{2} + 75 x + 124, - x^{3} + 15 x^{2} + 75 x + 124

Solution steps

Replace

x

with

y

Solve for

x^{3} + 15 x^{2} + 75 x + 124, - x^{3} + 15 x^{2} + 75 x + 124

20

2 x^{3} - 10

f (x) = \frac{x - 3}{5 x - 1}

2 π s - 1

a \cdot b = a + b + 2

What is the inverse of f(x)=\sqrt[3]{(x^2+1)}-5 ?
The inverse of f(x)=\sqrt[3]{(x^2+1)}-5 is sqrt(x^3+15x^2+75x+124),-sqrt(x^3+15x^2+75x+124)