What is the inverse of f(x)=sqrt(9-2x^2) ?

The inverse of f(x)=sqrt(9-2x^2) is sqrt(-(x^2-9)/2),-sqrt(-(x^2-9)/2)

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inverse of f(x)=sqrt(9-2x^2)

inverse

f (x) = 9 - 2 x^{2}

- \frac{x ^{2} - 9}{2}, - - \frac{x ^{2} - 9}{2}

Solution steps

y = 9 - 2 x^{2}

Replace

x

with

y

x = 9 - 2 y^{2}

Solve for

y, x = 9 - 2 y^{2}

- \frac{x ^{2} - 9}{2}, - - \frac{x ^{2} - 9}{2}

f (x) = \frac{( 5 x - 3 )}{2 x + 3}

f (x) = - 4 x^{2} + 2

\frac{1}{x + 3} + 2

arctan (- 3)

f (x) = \frac{( 9 x + 7 )}{2}

What is the inverse of f(x)=sqrt(9-2x^2) ?
The inverse of f(x)=sqrt(9-2x^2) is sqrt(-(x^2-9)/2),-sqrt(-(x^2-9)/2)