What is the inverse of y= 2/(sqrt(-x+4)) ?

The inverse of y= 2/(sqrt(-x+4)) is -(4-4x^2)/(x^2)

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inverse of y= 2/(sqrt(-x+4))

inverse

y = \frac{2}{- x + 4}

- \frac{4 - 4 x ^{2}}{x ^{2}}

Solution steps

y = \frac{2}{- x + 4}

Replace

x

with

y

x = \frac{2}{- y + 4}

Solve for

y, x = \frac{2}{- y + 4}

- \frac{4 - 4 x ^{2}}{x ^{2}}

+ 2 tan (x - \frac{π}{4})

(8 - 2 x)^{2}

2 + x - 6

f (x) = (3 x - 2)^{3}

ln (5)

What is the inverse of y= 2/(sqrt(-x+4)) ?
The inverse of y= 2/(sqrt(-x+4)) is -(4-4x^2)/(x^2)