What is the inverse of f(x)=-x^2-2x ?

The inverse of f(x)=-x^2-2x is -1-sqrt(-x+1),-1+sqrt(-x+1)

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inverse of f(x)=-x^2-2x

inverse

f (x) = - x^{2} - 2 x

- 1 - - x + 1, - 1 + - x + 1

Solution steps

y = - x^{2} - 2 x

Replace

x

with

y

x = - y^{2} - 2 y

Solve for

y, x = - y^{2} - 2 y

- 1 - - x + 1, - 1 + - x + 1

\frac{x + 2}{x + 8}

5 cos (4 x)

\frac{x + 2}{x + 6}

f (x) = 0.3 x - 18

f (x) = \frac{2 x + 7}{x + 2}

What is the inverse of f(x)=-x^2-2x ?
The inverse of f(x)=-x^2-2x is -1-sqrt(-x+1),-1+sqrt(-x+1)