What is the inverse of f(x)=11x^2+1 ?

The inverse of f(x)=11x^2+1 is sqrt((x-1)/(11)),-sqrt((x-1)/(11))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=11x^2+1

inverse

f (x) = 11 x^{2} + 1

\frac{x - 1}{11}, - \frac{x - 1}{11}

Solution steps

y = 11 x^{2} + 1

Replace

x

with

y

x = 11 y^{2} + 1

Solve for

y, x = 11 y^{2} + 1

\frac{x - 1}{11}, - \frac{x - 1}{11}

e^{(2 x + 1)}

2 x + 4 + x^{2}, - 3 < x < 2

f (x) = 3 sin (x) - 6

f (x) = 6 x^{2} + 9 x - 2

f (x) = \frac{( - y ^{2} + 6 y + 28 )}{60}

What is the inverse of f(x)=11x^2+1 ?
The inverse of f(x)=11x^2+1 is sqrt((x-1)/(11)),-sqrt((x-1)/(11))