What is the inverse of f(x)= 1/(sqrt(3x+5)) ?

The inverse of f(x)= 1/(sqrt(3x+5)) is (1-5x^2)/(3x^2)

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inverse of f(x)= 1/(sqrt(3x+5))

inverse

f (x) = \frac{1}{3 x + 5}

\frac{1 - 5 x ^{2}}{3 x ^{2}}

Solution steps

y = \frac{1}{3 x + 5}

Replace

x

with

y

x = \frac{1}{3 y + 5}

Solve for

y, x = \frac{1}{3 y + 5}

\frac{1 - 5 x ^{2}}{3 x ^{2}}

y = 5 x - 15

f (x) = 4 + x^{2}

f (x) = ln (x)

f (x) = 3 x^{3} - 2

f (x) = lo g_{2} (x - 5) + 1

What is the inverse of f(x)= 1/(sqrt(3x+5)) ?
The inverse of f(x)= 1/(sqrt(3x+5)) is (1-5x^2)/(3x^2)