What is the inverse of f(x)=11x^2+13 ?

The inverse of f(x)=11x^2+13 is sqrt((x-13)/(11)),-sqrt((x-13)/(11))

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inverse of f(x)=11x^2+13

inverse

f (x) = 11 x^{2} + 13

\frac{x - 13}{11}, - \frac{x - 13}{11}

Solution steps

y = 11 x^{2} + 13

Replace

x

with

y

x = 11 y^{2} + 13

Solve for

y, x = 11 y^{2} + 13

\frac{x - 13}{11}, - \frac{x - 13}{11}

\frac{1}{x + 1} - 1

f (x) = ln (\frac{1 + x}{1 - x})

f (x) = e^{3 x + 2} + 3

f (x) = 2 tan (\frac{y}{3})

f (x) = - 2 (x + 1) (x + 5)

What is the inverse of f(x)=11x^2+13 ?
The inverse of f(x)=11x^2+13 is sqrt((x-13)/(11)),-sqrt((x-13)/(11))