What is the inverse of f(x)=x^2+4x+16 ?

The inverse of f(x)=x^2+4x+16 is -2+sqrt(x-12),-sqrt(x-12)-2

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inverse of f(x)=x^2+4x+16

inverse

f (x) = x^{2} + 4 x + 16

- 2 + x - 12, - x - 12 - 2

Solution steps

y = x^{2} + 4 x + 16

Replace

x

with

y

x = y^{2} + 4 y + 16

Solve for

y, x = y^{2} + 4 y + 16

- 2 + x - 12, - x - 12 - 2

f (x) = f (x) = 3^{x}

f (x) = \frac{( x - 2 )}{x - 1}

\frac{x ^{3} - 8}{x - 2}

y = 6 - (- \frac{2}{3} cos (x))^{2} + 1

\frac{4 x - 5}{2 x + 1}

What is the inverse of f(x)=x^2+4x+16 ?
The inverse of f(x)=x^2+4x+16 is -2+sqrt(x-12),-sqrt(x-12)-2