What is the inverse of f(x)=3x^2+6x+10 ?

The inverse of f(x)=3x^2+6x+10 is (-6+sqrt(12x-84))/6 ,(-6-sqrt(12x-84))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3x^2+6x+10

inverse

f (x) = 3 x^{2} + 6 x + 10

\frac{- 6 + 12 x - 84}{6}, \frac{- 6 - 12 x - 84}{6}

Solution steps

y = 3 x^{2} + 6 x + 10

Replace

x

with

y

x = 3 y^{2} + 6 y + 10

Solve for

y, x = 3 y^{2} + 6 y + 10

\frac{- 6 + 12 x - 84}{6}, \frac{- 6 - 12 x - 84}{6}

sec (θ)

f (x) = \frac{200}{x ^{3}}

1 - e^{- λ x}

(x + 3)^{4}

f (x) = x - x - 1

What is the inverse of f(x)=3x^2+6x+10 ?
The inverse of f(x)=3x^2+6x+10 is (-6+sqrt(12x-84))/6 ,(-6-sqrt(12x-84))/6