What is the inverse of f(x)=10\sqrt[3]{-2x-5}+8 ?

The inverse of f(x)=10\sqrt[3]{-2x-5}+8 is -(x^3-24x^2+192x+4488)/(2000)

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inverse of f(x)=10\sqrt[3]{-2x-5}+8

inverse

f (x) = 10 3 - 2 x - 5 + 8

- \frac{x ^{3} - 24 x ^{2} + 192 x + 4488}{2000}

Solution steps

y = 10 3 - 2 x - 5 + 8

Replace

x

with

y

x = 10 3 - 2 y - 5 + 8

Solve for

y, x = 10 3 - 2 y - 5 + 8

- \frac{x ^{3} - 24 x ^{2} + 192 x + 4488}{2000}

f (x) = arcsin (y)

f (x) = 8 x + 5

\frac{1}{( x + 1 )}

f (x) = \frac{5 ( 1 - 2 x )}{4}

\frac{x ^{3} + 1}{x ^{3} + 2}

What is the inverse of f(x)=10\sqrt[3]{-2x-5}+8 ?
The inverse of f(x)=10\sqrt[3]{-2x-5}+8 is -(x^3-24x^2+192x+4488)/(2000)