What is the inverse of f(x)=((-y^2+10y+35))/(60) ?

The inverse of f(x)=((-y^2+10y+35))/(60) is -(-10+sqrt(-240y+240))/2 ,-(-10-sqrt(-240y+240))/2

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inverse of f(x)=((-y^2+10y+35))/(60)

inverse

f (x) = \frac{( - y ^{2} + 10 y + 35 )}{60}

- \frac{- 10 + - 240 y + 240}{2}, - \frac{- 10 - - 240 y + 240}{2}

Solution steps

x = \frac{- y ^{2} + 10 y + 35}{60}

Replace

y

with

x

y = \frac{- x ^{2} + 10 x + 35}{60}

Solve for

x, y = \frac{- x ^{2} + 10 x + 35}{60}

- \frac{- 10 + - 240 y + 240}{2}, - \frac{- 10 - - 240 y + 240}{2}

f (x) = \frac{( - x - 2 )}{x + 4}

x^{2} + 11

f (x) = 1 - 2 x + 2

f (x) = \frac{- 3 x + 8}{6 + x}

y = \frac{7 x - 1}{3 x + 2}

What is the inverse of f(x)=((-y^2+10y+35))/(60) ?
The inverse of f(x)=((-y^2+10y+35))/(60) is -(-10+sqrt(-240y+240))/2 ,-(-10-sqrt(-240y+240))/2