What is the inverse of (x^2)/(2x^2+4) ?

The inverse of (x^2)/(2x^2+4) is sqrt(-(4x)/(2x-1)),-sqrt(-(4x)/(2x-1))

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inverse of (x^2)/(2x^2+4)

inverse

\frac{x ^{2}}{2 x ^{2} + 4}

- \frac{4 x}{2 x - 1}, - - \frac{4 x}{2 x - 1}

Solution steps

y = \frac{x ^{2}}{2 x ^{2} + 4}

Replace

x

with

y

x = \frac{y ^{2}}{2 y ^{2} + 4}

Solve for

y, x = \frac{y ^{2}}{2 y ^{2} + 4}

- \frac{4 x}{2 x - 1}, - - \frac{4 x}{2 x - 1}

\frac{8}{3 + x ^{2}}

\frac{e ^{- 3 x} + 4}{2} + 1

h (x) = x^{2} + 1

f (x) = \frac{x ^{2} + x + 6}{4 - x ^{2}}

\frac{2}{x + 13}

What is the inverse of (x^2)/(2x^2+4) ?
The inverse of (x^2)/(2x^2+4) is sqrt(-(4x)/(2x-1)),-sqrt(-(4x)/(2x-1))