What is the inverse of f(x)=-8x^2+4x ?

The inverse of f(x)=-8x^2+4x is -(-1+sqrt(-2x+1))/4 ,(sqrt(-2x+1)+1)/4

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inverse of f(x)=-8x^2+4x

inverse

f (x) = - 8 x^{2} + 4 x

- \frac{- 1 + - 2 x + 1}{4}, \frac{- 2 x + 1 + 1}{4}

Solution steps

y = - 8 x^{2} + 4 x

Replace

x

with

y

x = - 8 y^{2} + 4 y

Solve for

y, x = - 8 y^{2} + 4 y

- \frac{- 1 + - 2 x + 1}{4}, \frac{- 2 x + 1 + 1}{4}

f (x) = \frac{6 x}{x - 5}

f (x) = 4 x + 19

\frac{1}{6} x^{3} - 3

\frac{1}{6} x^{3} - 5

f (x) = \frac{x - 2}{x - 4}

What is the inverse of f(x)=-8x^2+4x ?
The inverse of f(x)=-8x^2+4x is -(-1+sqrt(-2x+1))/4 ,(sqrt(-2x+1)+1)/4