What is the inverse of y= 1/2 (x-1)^2-2 ?

The inverse of y= 1/2 (x-1)^2-2 is sqrt(2x+4)+1,-sqrt(2x+4)+1

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inverse of y= 1/2 (x-1)^2-2

inverse

y = \frac{1}{2} (x - 1)^{2} - 2

2 x + 4 + 1, - 2 x + 4 + 1

Solution steps

y = \frac{1}{2} (x - 1)^{2} - 2

Replace

x

with

y

x = \frac{1}{2} (y - 1)^{2} - 2

Solve for

y, x = \frac{1}{2} (y - 1)^{2} - 2

2 x + 4 + 1, - 2 x + 4 + 1

f (x) = \frac{8 x}{7 x + 1}

a^{4} - a^{2} + 1

f (x) = \frac{1 + 6 x}{4 - 3 x}

f (x) = \frac{( x + 3 )}{x + 8}

\frac{5 x}{4 x - 7}

What is the inverse of y= 1/2 (x-1)^2-2 ?
The inverse of y= 1/2 (x-1)^2-2 is sqrt(2x+4)+1,-sqrt(2x+4)+1