What is the inverse of f(x)= 2/5 (25x-1)-3= 1/2-10x ?

The inverse of f(x)= 2/5 (25x-1)-3= 1/2-10x is -(2x-1)/(20)

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inverse of f(x)= 2/5 (25x-1)-3= 1/2-10x

inverse

f (x) = \frac{2}{5} (25 x - 1) - 3 = \frac{1}{2} - 10 x

- \frac{2 x - 1}{20}

Solution steps

y = \frac{1}{2} - 10 x

Replace

x

with

y

x = \frac{1}{2} - 10 y

Solve for

y, x = \frac{1}{2} - 10 y

- \frac{2 x - 1}{20}

y = x^{2} - 4 x + 2

f (x) = x + 20

f (x) = x^{2} - 8 x - 84

\frac{3 - 2}{2 x - 5}

f (x) = \frac{12 - 3 x}{4}

What is the inverse of f(x)= 2/5 (25x-1)-3= 1/2-10x ?
The inverse of f(x)= 2/5 (25x-1)-3= 1/2-10x is -(2x-1)/(20)