What is the inverse of f(x)=(-7-x)/(8x-5) ?

The inverse of f(x)=(-7-x)/(8x-5) is (-7+5x)/(8x+1)

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inverse of f(x)=(-7-x)/(8x-5)

inverse

f (x) = \frac{- 7 - x}{8 x - 5}

\frac{- 7 + 5 x}{8 x + 1}

Solution steps

y = \frac{- 7 - x}{8 x - 5}

Replace

x

with

y

x = \frac{- 7 - y}{8 y - 5}

Solve for

y, x = \frac{- 7 - y}{8 y - 5}

\frac{- 7 + 5 x}{8 x + 1}

f (x) = 2 x^{11} + 2

f (x) = (x - 7)^{2} + 1, x \leq 7

\frac{5 x}{x + 7}

f (x) = \frac{( 3 x + 5 )}{2}

\frac{x ^{2} + 1}{x ^{4} + 3 x ^{2} + 1}

What is the inverse of f(x)=(-7-x)/(8x-5) ?
The inverse of f(x)=(-7-x)/(8x-5) is (-7+5x)/(8x+1)