What is the inverse of f(x)=sqrt(1-log_{2)(x)} ?

The inverse of f(x)=sqrt(1-log_{2)(x)} is 2^{1-x^2}

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inverse of f(x)=sqrt(1-log_{2)(x)}

inverse

f (x) = 1 - lo g_{2} (x)

2^{1 - x^{2}}

Solution steps

y = 1 - lo g_{2} (x)

Replace

x

with

y

x = 1 - lo g_{2} (y)

Solve for

y, x = 1 - lo g_{2} (y)

2^{1 - x^{2}}

f (x) = \frac{1}{8} (\frac{1}{2} x^{2} + 2 x + 2)

f (x) = 5 e^{y}

f (x) = \frac{x - 1}{x + 6}

f (x) = \frac{- x + 5}{2 x - 3}

+ 8 x - 7

What is the inverse of f(x)=sqrt(1-log_{2)(x)} ?
The inverse of f(x)=sqrt(1-log_{2)(x)} is 2^{1-x^2}