What is the inverse of (2^{4x-1}*3^{x-2})/(12^{x-2)} ?

The inverse of (2^{4x-1}*3^{x-2})/(12^{x-2)} is (ln(x)-3ln(2))/(2ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (2^{4x-1}*3^{x-2})/(12^{x-2)}

inverse

\frac{2 ^{4 x - 1} \cdot 3 ^{x - 2}}{1 2 ^{x - 2}}

\frac{ln ( x ) - 3 ln ( 2 )}{2 ln ( 2 )}

Solution steps

y = \frac{2 ^{4 x - 1} \cdot 3 ^{x - 2}}{1 2 ^{x - 2}}

Replace

x

with

y

x = \frac{2 ^{4 y - 1} \cdot 3 ^{y - 2}}{1 2 ^{y - 2}}

Solve for

y, x = \frac{2 ^{4 y - 1} \cdot 3 ^{y - 2}}{1 2 ^{y - 2}}

\frac{ln ( x ) - 3 ln ( 2 )}{2 ln ( 2 )}

\frac{6 x - 2}{2 x + 6}

\frac{23 - 3 x}{6 x}

f (x) = 3 ln (x) - 2

f (x) = e^{s i n (x)}

f (x) = 0.2 x^{0.5}

What is the inverse of (2^{4x-1}*3^{x-2})/(12^{x-2)} ?
The inverse of (2^{4x-1}*3^{x-2})/(12^{x-2)} is (ln(x)-3ln(2))/(2ln(2))