What is the inverse of sqrt((2x+7)/(3x-4)) ?

The inverse of sqrt((2x+7)/(3x-4)) is (7+4x^2)/(3x^2-2)

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inverse of sqrt((2x+7)/(3x-4))

inverse

\frac{2 x + 7}{3 x - 4}

\frac{7 + 4 x ^{2}}{3 x ^{2} - 2}

Solution steps

y = \frac{2 x + 7}{3 x - 4}

Replace

x

with

y

x = \frac{2 y + 7}{3 y - 4}

Solve for

y, x = \frac{2 y + 7}{3 y - 4}

\frac{7 + 4 x ^{2}}{3 x ^{2} - 2}

f (x) = (x + 5)^{4}

y = x - 1 + 4

f (x) = 7000 - 1000 y

f (x) = lo g_{x} (3)

f (x) = lo g_{4} (2 x) - 5

What is the inverse of sqrt((2x+7)/(3x-4)) ?
The inverse of sqrt((2x+7)/(3x-4)) is (7+4x^2)/(3x^2-2)