What is the inverse of f(x)=x^2-14,x>= 0 ?

The inverse of f(x)=x^2-14,x>= 0 is sqrt(x+14),-sqrt(x+14)

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inverse of f(x)=x^2-14,x>= 0

inverse

f (x) = x^{2} - 14, x \geq 0

x + 14, - x + 14

Solution steps

y = x^{2} - 14

Replace

x

with

y

x = y^{2} - 14

Solve for

y, x = y^{2} - 14

x + 14, - x + 14

y = - (x - 5)^{2}

f (x) = cos (8 x)

f (x) = x + \frac{1}{4}

T (x) = 2 π \frac{l}{9.8}

4 - 2 x + 5

What is the inverse of f(x)=x^2-14,x>= 0 ?
The inverse of f(x)=x^2-14,x>= 0 is sqrt(x+14),-sqrt(x+14)