What is the inverse of f(x)=(x)^{-1}=(5-2x)/(4x-2) ?

The inverse of f(x)=(x)^{-1}=(5-2x)/(4x-2) is (5+2x)/(2(1+2x))

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inverse of f(x)=(x)^{-1}=(5-2x)/(4x-2)

inverse

f (x) = (x)^{- 1} = \frac{5 - 2 x}{4 x - 2}

\frac{5 + 2 x}{2 ( 1 + 2 x )}

Solution steps

y = \frac{5 - 2 x}{4 x - 2}

Replace

x

with

y

x = \frac{5 - 2 y}{4 y - 2}

Solve for

y, x = \frac{5 - 2 y}{4 y - 2}

\frac{5 + 2 x}{2 ( 1 + 2 x )}

f (x) = 15 x + 15

g (x) = \frac{4 - x}{5}

1.175

f (x) = 15 x + 30

f (- 9) = \frac{x + 3}{x + 6}

What is the inverse of f(x)=(x)^{-1}=(5-2x)/(4x-2) ?
The inverse of f(x)=(x)^{-1}=(5-2x)/(4x-2) is (5+2x)/(2(1+2x))