What is the inverse of (x-1)/(x^2) ?

The inverse of (x-1)/(x^2) is (1+sqrt(1-4x))/(2x),(1-sqrt(1-4x))/(2x)

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inverse of (x-1)/(x^2)

inverse

\frac{x - 1}{x ^{2}}

\frac{1 + 1 - 4 x}{2 x}, \frac{1 - 1 - 4 x}{2 x}

Solution steps

y = \frac{x - 1}{x ^{2}}

Replace

x

with

y

x = \frac{y - 1}{y ^{2}}

Solve for

y, x = \frac{y - 1}{y ^{2}}

\frac{1 + 1 - 4 x}{2 x}, \frac{1 - 1 - 4 x}{2 x}

- x + 4

f (x) = \frac{x + 5}{2 x + 1}

4 x - 18

- 5 x - 2

e^{x + 4} + 2

What is the inverse of (x-1)/(x^2) ?
The inverse of (x-1)/(x^2) is (1+sqrt(1-4x))/(2x),(1-sqrt(1-4x))/(2x)