What is the inverse of f(x)=18500(0.25-r^2) ?

The inverse of f(x)=18500(0.25-r^2) is sqrt(-0.00005…r+0.25),-sqrt(-0.00005…r+0.25)

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inverse of f(x)=18500(0.25-r^2)

inverse

f (x) = 18500 (0.25 - r^{2})

- 0.00005 \dots r + 0.25, - - 0.00005 \dots r + 0.25

Solution steps

x = 18500 (0.25 - r^{2})

Replace

r

with

x

r = 18500 (0.25 - x^{2})

Solve for

x, r = 18500 (0.25 - x^{2})

- 0.00005 \dots r + 0.25, - - 0.00005 \dots r + 0.25

f (x) = ln (7 x + 4) - 2

f (x) = 9 x^{3} - 6

f (x) = - 7 cos (2 x)

f (x) = 2 π r^{2} + 2 π r 8

f (x) = 9 x^{3} + 8

What is the inverse of f(x)=18500(0.25-r^2) ?
The inverse of f(x)=18500(0.25-r^2) is sqrt(-0.00005…r+0.25),-sqrt(-0.00005…r+0.25)