What is the inverse of f(x)=8x^2-3 ?

The inverse of f(x)=8x^2-3 is (sqrt(2)sqrt(x+3))/4 ,-(sqrt(2)sqrt(x+3))/4

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inverse of f(x)=8x^2-3

inverse

f (x) = 8 x^{2} - 3

\frac{2 x + 3}{4}, - \frac{2 x + 3}{4}

Solution steps

y = 8 x^{2} - 3

Replace

x

with

y

x = 8 y^{2} - 3

Solve for

y, x = 8 y^{2} - 3

\frac{2 x + 3}{4}, - \frac{2 x + 3}{4}

f (x) = \frac{x}{4 + 3 x}

f (x) = 11 x^{3} - 10

f (x) = \frac{2}{x - 1} - 3

f (x) = f (x) = 2 x + 5

What is the inverse of f(x)=8x^2-3 ?
The inverse of f(x)=8x^2-3 is (sqrt(2)sqrt(x+3))/4 ,-(sqrt(2)sqrt(x+3))/4