What is the inverse of f(x)=-2(x-1)^2+4 ?

The inverse of f(x)=-2(x-1)^2+4 is sqrt(-(x-4)/2)+1,-sqrt(-(x-4)/2)+1

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inverse of f(x)=-2(x-1)^2+4

inverse

f (x) = - 2 (x - 1)^{2} + 4

- \frac{x - 4}{2} + 1, - - \frac{x - 4}{2} + 1

Solution steps

y = - 2 (x - 1)^{2} + 4

Replace

x

with

y

x = - 2 (y - 1)^{2} + 4

Solve for

y, x = - 2 (y - 1)^{2} + 4

- \frac{x - 4}{2} + 1, - - \frac{x - 4}{2} + 1

ln (x - 5) + 3

f (x) = - \frac{7}{9} x + 7

\frac{x - 1}{x - 2}

f (x) = - \frac{1}{7} 16 - x^{2}

What is the inverse of f(x)=-2(x-1)^2+4 ?
The inverse of f(x)=-2(x-1)^2+4 is sqrt(-(x-4)/2)+1,-sqrt(-(x-4)/2)+1