What is the inverse of f(x)=17x^2-23 ?

The inverse of f(x)=17x^2-23 is sqrt((x+23)/(17)),-sqrt((x+23)/(17))

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inverse of f(x)=17x^2-23

inverse

f (x) = 17 x^{2} - 23

\frac{x + 23}{17}, - \frac{x + 23}{17}

Solution steps

y = 17 x^{2} - 23

Replace

x

with

y

x = 17 y^{2} - 23

Solve for

y, x = 17 y^{2} - 23

\frac{x + 23}{17}, - \frac{x + 23}{17}

\frac{x - 1}{x - 3}

y = e^{5 - x}

f (x) = 7 x^{2} + 8, x \geq 0

\frac{x ^{3}}{4}

f (x) = \frac{2 x + 5}{4}

What is the inverse of f(x)=17x^2-23 ?
The inverse of f(x)=17x^2-23 is sqrt((x+23)/(17)),-sqrt((x+23)/(17))