What is the inverse of 4cos^2(x) ?

The inverse of 4cos^2(x) is arccos((sqrt(x))/2),arccos(-(sqrt(x))/2)

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inverse of 4cos^2(x)

inverse

4 cos^{2} (x)

arccos (\frac{x}{2}), arccos (- \frac{x}{2})

Solution steps

Solve for

cos (x), y = 4 cos^{2} (x)

cos (x) = \frac{y}{2}, cos (x) = - \frac{y}{2}

cos (a) = b \Rightarrow a = arccos (b)

arccos (\frac{y}{2}), arccos (- \frac{y}{2})

Substitute

y = x

arccos (\frac{x}{2}), arccos (- \frac{x}{2})

\frac{4 x - 1}{2 x + 1}

f (x) = - \frac{3}{7} x + \frac{15}{7}

\frac{4}{x ^{2} - 1}

\frac{x ^{5} - 2}{3}

\frac{8 x ^{2} + 26 x - 7}{4 x - 1}

What is the inverse of 4cos^2(x) ?
The inverse of 4cos^2(x) is arccos((sqrt(x))/2),arccos(-(sqrt(x))/2)