What is the inverse of f(x)=-2x^2+8x-7,x>2 ?

The inverse of f(x)=-2x^2+8x-7,x>2 is -(-8+sqrt(-8x+8))/4 ,-(-8-sqrt(-8x+8))/4

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inverse of f(x)=-2x^2+8x-7,x>2

inverse

f (x) = - 2 x^{2} + 8 x - 7, x > 2

- \frac{- 8 + - 8 x + 8}{4}, - \frac{- 8 - - 8 x + 8}{4}

Solution steps

y = - 2 x^{2} + 8 x - 7

Replace

x

with

y

x = - 2 y^{2} + 8 y - 7

Solve for

y, x = - 2 y^{2} + 8 y - 7

- \frac{- 8 + - 8 x + 8}{4}, - \frac{- 8 - - 8 x + 8}{4}

lo g_{2} (11 x) + 4

f (x) = 4 cos (π x + \frac{π}{2})

7^{t - 2}

f (x) = \frac{4}{4 - x}

ln (x) 6

What is the inverse of f(x)=-2x^2+8x-7,x>2 ?
The inverse of f(x)=-2x^2+8x-7,x>2 is -(-8+sqrt(-8x+8))/4 ,-(-8-sqrt(-8x+8))/4