What is the inverse of f(x)=-2(x-2)^2-3 ?

The inverse of f(x)=-2(x-2)^2-3 is sqrt(-(x+3)/2)+2,-sqrt(-(x+3)/2)+2

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inverse of f(x)=-2(x-2)^2-3

inverse

f (x) = - 2 (x - 2)^{2} - 3

- \frac{x + 3}{2} + 2, - - \frac{x + 3}{2} + 2

Solution steps

y = - 2 (x - 2)^{2} - 3

Replace

x

with

y

x = - 2 (y - 2)^{2} - 3

Solve for

y, x = - 2 (y - 2)^{2} - 3

- \frac{x + 3}{2} + 2, - - \frac{x + 3}{2} + 2

\frac{x - 2}{x + 4}

2^{x} + 5

\frac{- 7 x + 5}{3 x + 9}

f (x) = 3 \frac{( x ^{5} )}{2} - 7

\frac{1}{7}

What is the inverse of f(x)=-2(x-2)^2-3 ?
The inverse of f(x)=-2(x-2)^2-3 is sqrt(-(x+3)/2)+2,-sqrt(-(x+3)/2)+2