What is the inverse of f(x)=4-x^2-2x ?

The inverse of f(x)=4-x^2-2x is -1-sqrt(-x+5),-1+sqrt(-x+5)

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inverse of f(x)=4-x^2-2x

inverse

f (x) = 4 - x^{2} - 2 x

- 1 - - x + 5, - 1 + - x + 5

Solution steps

y = 4 - x^{2} - 2 x

Replace

x

with

y

x = 4 - y^{2} - 2 y

Solve for

y, x = 4 - y^{2} - 2 y

- 1 - - x + 5, - 1 + - x + 5

f (x) = \frac{( \frac{x + 1}{2} )}{2}

f (x) = 10 - \frac{10}{3} x

+ x^{2} - 8 x + 15

f (x) = \frac{1}{2 x - x ^{2}}

f (x) = (x + 10)^{5}

What is the inverse of f(x)=4-x^2-2x ?
The inverse of f(x)=4-x^2-2x is -1-sqrt(-x+5),-1+sqrt(-x+5)