What is the inverse of sqrt(x^2+4)+1 ?

The inverse of sqrt(x^2+4)+1 is sqrt(x^2-2x-3),-sqrt(x^2-2x-3)

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inverse of sqrt(x^2+4)+1

inverse

x^{2} + 4 + 1

x^{2} - 2 x - 3, - x^{2} - 2 x - 3

Solution steps

y = x^{2} + 4 + 1

Replace

x

with

y

x = y^{2} + 4 + 1

Solve for

y, x = y^{2} + 4 + 1

x^{2} - 2 x - 3, - x^{2} - 2 x - 3

f (x) = x^{3 + 8}

f (x) = 100 (\frac{1 - t}{40})^{2}

f (x) = 1 - 2 x - x^{2}

f (x) = x^{2} + 3 x + 4

x^{2} + x - 2

What is the inverse of sqrt(x^2+4)+1 ?
The inverse of sqrt(x^2+4)+1 is sqrt(x^2-2x-3),-sqrt(x^2-2x-3)