What is the inverse of f(x)=x^{3+1} ?

The inverse of f(x)=x^{3+1} is \sqrt[4]{x},-\sqrt[4]{x}

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inverse of f(x)=x^{3+1}

inverse

f (x) = x^{3 + 1}

4 x, - 4 x

Solution steps

y = x^{3 + 1}

Replace

x

with

y

x = y^{3 + 1}

Solve for

y, x = y^{3 + 1}

4 x, - 4 x

f (x) = x^{2} - 6 x, 3 \leq x \leq 5

f (x) = - \frac{4}{3}

f (x) = x^{4} - 8 x^{2} + 7

f (x) = \frac{2 x - 6}{3 x + 2}

\frac{s + 1}{s - 2}

What is the inverse of f(x)=x^{3+1} ?
The inverse of f(x)=x^{3+1} is \sqrt[4]{x},-\sqrt[4]{x}