What is the inverse of y=7x^2+4x-3 ?

The inverse of y=7x^2+4x-3 is (-2+sqrt(7x+25))/7 ,-(sqrt(7x+25)+2)/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=7x^2+4x-3

inverse

y = 7 x^{2} + 4 x - 3

\frac{- 2 + 7 x + 25}{7}, - \frac{7 x + 25 + 2}{7}

Solution steps

y = 7 x^{2} + 4 x - 3

Replace

x

with

y

x = 7 y^{2} + 4 y - 3

Solve for

y, x = 7 y^{2} + 4 y - 3

\frac{- 2 + 7 x + 25}{7}, - \frac{7 x + 25 + 2}{7}

- 2 x - 2 + 6

\frac{9 x}{x + 2}

\frac{1 - x}{x}

\frac{2 x - 3}{x}

x^{2} + 10 x

What is the inverse of y=7x^2+4x-3 ?
The inverse of y=7x^2+4x-3 is (-2+sqrt(7x+25))/7 ,-(sqrt(7x+25)+2)/7