What is the inverse of f(x)=(x-2)^2+4,x>= 2 ?

The inverse of f(x)=(x-2)^2+4,x>= 2 is sqrt(x-4)+2,-sqrt(x-4)+2

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inverse of f(x)=(x-2)^2+4,x>= 2

inverse

f (x) = (x - 2)^{2} + 4, x \geq 2

x - 4 + 2, - x - 4 + 2

Solution steps

y = (x - 2)^{2} + 4

Replace

x

with

y

x = (y - 2)^{2} + 4

Solve for

y, x = (y - 2)^{2} + 4

x - 4 + 2, - x - 4 + 2

\frac{2 x + 1}{3 - 2 x}

f (x) = 5 x + 13 + 5

6 x

1 - \frac{2}{x}

f (x) = (x)^{\frac{1}{3}} + 1

What is the inverse of f(x)=(x-2)^2+4,x>= 2 ?
The inverse of f(x)=(x-2)^2+4,x>= 2 is sqrt(x-4)+2,-sqrt(x-4)+2