What is the inverse of 5/(s^2-3s+3) ?

The inverse of 5/(s^2-3s+3) is (3s+sqrt(-3s^2+20s))/(2s),(3s-sqrt(-3s^2+20s))/(2s)

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inverse of 5/(s^2-3s+3)

inverse

\frac{5}{s ^{2} - 3 s + 3}

\frac{3 s + - 3 s ^{2} + 20 s}{2 s}, \frac{3 s - - 3 s ^{2} + 20 s}{2 s}

Solution steps

y = \frac{5}{s ^{2} - 3 s + 3}

Replace

s

with

y

s = \frac{5}{y ^{2} - 3 y + 3}

Solve for

y, s = \frac{5}{y ^{2} - 3 y + 3}

\frac{3 s + - 3 s ^{2} + 20 s}{2 s}, \frac{3 s - - 3 s ^{2} + 20 s}{2 s}

g (s) = 65 t

f (x) = \frac{3}{x - 3} + 1

f (x) = 2 - e^{x + 3}

25200 + 28 b^{2}

f (x) = - \frac{7}{8} x + 7

What is the inverse of 5/(s^2-3s+3) ?
The inverse of 5/(s^2-3s+3) is (3s+sqrt(-3s^2+20s))/(2s),(3s-sqrt(-3s^2+20s))/(2s)