What is the inverse of f(x)=(4x-1)/(7x+5) ?

The inverse of f(x)=(4x-1)/(7x+5) is (-1-5x)/(7x-4)

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inverse of f(x)=(4x-1)/(7x+5)

inverse

f (x) = \frac{4 x - 1}{7 x + 5}

\frac{- 1 - 5 x}{7 x - 4}

Solution steps

y = \frac{4 x - 1}{7 x + 5}

Replace

x

with

y

x = \frac{4 y - 1}{7 y + 5}

Solve for

y, x = \frac{4 y - 1}{7 y + 5}

\frac{- 1 - 5 x}{7 x - 4}

f (x) = \frac{( 5 x + 2 )}{( 3 - x )}

lo g_{x} (2)

f (x) = arccos (\frac{4 - x}{3 + x})

\frac{6}{8 - x}

\frac{x}{3} - 2

What is the inverse of f(x)=(4x-1)/(7x+5) ?
The inverse of f(x)=(4x-1)/(7x+5) is (-1-5x)/(7x-4)