What is the inverse of f(x)=(400)/(x^2) ?

The inverse of f(x)=(400)/(x^2) is (20sqrt(x))/x ,-(20sqrt(x))/x

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inverse of f(x)=(400)/(x^2)

inverse

f (x) = \frac{400}{x ^{2}}

\frac{20 x}{x}, - \frac{20 x}{x}

Solution steps

y = \frac{400}{x ^{2}}

Replace

x

with

y

x = \frac{400}{y ^{2}}

Solve for

y, x = \frac{400}{y ^{2}}

\frac{20 x}{x}, - \frac{20 x}{x}

f (x) = 2 x^{(2)} - 3 x - 1

f (x) = \frac{- 6 x + 2}{- 8 x + 9}

f (x) = \frac{9}{- 8 x - 9}

ln (x - 7)

7 x^{2} - 6 x - 1

What is the inverse of f(x)=(400)/(x^2) ?
The inverse of f(x)=(400)/(x^2) is (20sqrt(x))/x ,-(20sqrt(x))/x