What is the inverse of f(x)=((x-1))/((x+5)) ?

The inverse of f(x)=((x-1))/((x+5)) is (-1-5x)/(x-1)

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inverse of f(x)=((x-1))/((x+5))

inverse

f (x) = \frac{( x - 1 )}{( x + 5 )}

\frac{- 1 - 5 x}{x - 1}

Solution steps

y = \frac{x - 1}{x + 5}

Replace

x

with

y

x = \frac{y - 1}{y + 5}

Solve for

y, x = \frac{y - 1}{y + 5}

\frac{- 1 - 5 x}{x - 1}

f (x) = - 0.5 (e^{2 x} - 1)

f (x) = \frac{7}{x} - 2

4 (x - 7)^{2} + 3, x \leq 7

f (x) = \frac{3 x + 9}{4}

f (x) = (2 x - 5)^{3}

What is the inverse of f(x)=((x-1))/((x+5)) ?
The inverse of f(x)=((x-1))/((x+5)) is (-1-5x)/(x-1)