What is the inverse of f(x)=sqrt(2x^2+4x+2) ?

The inverse of f(x)=sqrt(2x^2+4x+2) is (-2+sqrt(2)x)/2 ,-(sqrt(2)x+2)/2

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inverse of f(x)=sqrt(2x^2+4x+2)

inverse

f (x) = 2 x^{2} + 4 x + 2

\frac{- 2 + 2 x}{2}, - \frac{2 x + 2}{2}

Solution steps

y = 2 x^{2} + 4 x + 2

Replace

x

with

y

x = 2 y^{2} + 4 y + 2

Solve for

y, x = 2 y^{2} + 4 y + 2

\frac{- 2 + 2 x}{2}, - \frac{2 x + 2}{2}

f (x) = 3 e^{- 2 x}

z \frac{z}{z - 1}

f (x) = \frac{5 x - 2}{2 x + 1}

f (x) = \frac{e ^{x}}{5 + 4 e ^{x}}

f (x) = - 3 (x - 1)^{2} + 5

What is the inverse of f(x)=sqrt(2x^2+4x+2) ?
The inverse of f(x)=sqrt(2x^2+4x+2) is (-2+sqrt(2)x)/2 ,-(sqrt(2)x+2)/2