What is the inverse of 5-2log_{a}(3x+1) ?

The inverse of 5-2log_{a}(3x+1) is (a^{-(x-5)/2}-1)/(3)

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inverse of 5-2log_{a}(3x+1)

inverse

5 - 2 lo g_{a} (3 x + 1)

\frac{a ^{- \frac{x - 5}{2}} - 1}{3}

Solution steps

y = 5 - 2 lo g_{a} (3 x + 1)

Replace

x

with

y

x = 5 - 2 lo g_{a} (3 y + 1)

Solve for

y, x = 5 - 2 lo g_{a} (3 y + 1)

\frac{a ^{- \frac{x - 5}{2}} - 1}{3}

+ zz

2 - \frac{1}{x + 1}

f (x) = - \frac{1}{2} y

e^{3 \frac{x}{2}}

8 - 2 x^{3}

What is the inverse of 5-2log_{a}(3x+1) ?
The inverse of 5-2log_{a}(3x+1) is (a^{-(x-5)/2}-1)/(3)