What is the inverse of f(x)=19x^6-38 ?

The inverse of f(x)=19x^6-38 is \sqrt[6]{(x+38)/(19)},-\sqrt[6]{(x+38)/(19)}

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inverse of f(x)=19x^6-38

inverse

f (x) = 19 x^{6} - 38

Solution steps

y = 19 x^{6} - 38

Replace

x

with

y

x = 19 y^{6} - 38

Solve for

y, x = 19 y^{6} - 38

f (x) = cos (x - 7) + 4

f (x) = \frac{5000 x}{x + 100}

x^{4} - 32 x^{2} + 150

f (x) = x \cdot x^{- 0.3}

y = 7 - x^{2}

What is the inverse of f(x)=19x^6-38 ?
The inverse of f(x)=19x^6-38 is \sqrt[6]{(x+38)/(19)},-\sqrt[6]{(x+38)/(19)}