What is the inverse of f(x)=2x^2-9 ?

The inverse of f(x)=2x^2-9 is sqrt((x+9)/2),-sqrt((x+9)/2)

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inverse of f(x)=2x^2-9

inverse

f (x) = 2 x^{2} - 9

\frac{x + 9}{2}, - \frac{x + 9}{2}

Solution steps

y = 2 x^{2} - 9

Replace

x

with

y

x = 2 y^{2} - 9

Solve for

y, x = 2 y^{2} - 9

\frac{x + 9}{2}, - \frac{x + 9}{2}

y = 2 x - 5

f (x) = \frac{x}{9 x - 2}

f (x) = 2 + x

f (x) = lo g_{3} (x + 3) - 2

3 + lo g_{2} (x + 4)

What is the inverse of f(x)=2x^2-9 ?
The inverse of f(x)=2x^2-9 is sqrt((x+9)/2),-sqrt((x+9)/2)