What is the inverse of y=(9x-3)/(9x+7) ?

The inverse of y=(9x-3)/(9x+7) is (-3-7x)/(9(-1+x))

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inverse of y=(9x-3)/(9x+7)

inverse

y = \frac{9 x - 3}{9 x + 7}

\frac{- 3 - 7 x}{9 ( - 1 + x )}

Solution steps

y = \frac{9 x - 3}{9 x + 7}

Replace

x

with

y

x = \frac{9 y - 3}{9 y + 7}

Solve for

y, x = \frac{9 y - 3}{9 y + 7}

\frac{- 3 - 7 x}{9 ( - 1 + x )}

- \frac{1}{2} x + \frac{3}{4}

f (x) = 3 + ln (- 3 + 2 x)

f (x) = 2^{x^{2} - 1}

54.7928711

What is the inverse of y=(9x-3)/(9x+7) ?
The inverse of y=(9x-3)/(9x+7) is (-3-7x)/(9(-1+x))