What is the inverse of f(x)=(1/(x+3))^2 ?

The inverse of f(x)=(1/(x+3))^2 is sqrt(1/x)-3,-sqrt(1/x)-3

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inverse of f(x)=(1/(x+3))^2

inverse

f (x) = (\frac{1}{x + 3})^{2}

\frac{1}{x} - 3, - \frac{1}{x} - 3

Solution steps

y = (\frac{1}{x + 3})^{2}

Replace

x

with

y

x = (\frac{1}{y + 3})^{2}

Solve for

y, x = (\frac{1}{y + 3})^{2}

\frac{1}{x} - 3, - \frac{1}{x} - 3

3 x + 4

f (x) = \frac{7 x}{x - 5}

2^{3 x} - 4

11 + 4 x - 4

e^{- 2 t}

What is the inverse of f(x)=(1/(x+3))^2 ?
The inverse of f(x)=(1/(x+3))^2 is sqrt(1/x)-3,-sqrt(1/x)-3