What is the inverse of f(x)=((x-pi)^2)/x ?

The inverse of f(x)=((x-pi)^2)/x is (2pi+x+sqrt(x^2+4pix))/2 ,(2pi+x-sqrt(x^2+4pix))/2

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inverse of f(x)=((x-pi)^2)/x

inverse

f (x) = \frac{( x - π ) ^{2}}{x}

\frac{2 π + x + x ^{2} + 4 π x}{2}, \frac{2 π + x - x ^{2} + 4 π x}{2}

Solution steps

y = \frac{( x - π ) ^{2}}{x}

Replace

x

with

y

x = \frac{( y - π ) ^{2}}{y}

Solve for

y, x = \frac{( y - π ) ^{2}}{y}

\frac{2 π + x + x ^{2} + 4 π x}{2}, \frac{2 π + x - x ^{2} + 4 π x}{2}

\frac{1}{6 - 5 x} + 2

f (x) = \frac{1}{x + 6} + 4

\frac{3 x}{2 x - 1}

f (x) = \frac{e ^{x}}{5 + 2 e ^{x}}

f (x) = \frac{2 - x}{x + 5}

What is the inverse of f(x)=((x-pi)^2)/x ?
The inverse of f(x)=((x-pi)^2)/x is (2pi+x+sqrt(x^2+4pix))/2 ,(2pi+x-sqrt(x^2+4pix))/2