What is the inverse of f(x)=(x-3)^2-8,x>3 ?

The inverse of f(x)=(x-3)^2-8,x>3 is sqrt(x+8)+3,-sqrt(x+8)+3

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inverse of f(x)=(x-3)^2-8,x>3

inverse

f (x) = (x - 3)^{2} - 8, x > 3

x + 8 + 3, - x + 8 + 3

Solution steps

y = (x - 3)^{2} - 8

Replace

x

with

y

x = (y - 3)^{2} - 8

Solve for

y, x = (y - 3)^{2} - 8

x + 8 + 3, - x + 8 + 3

- 7 x - 4

- 3 - 2 x + 3

arctan (4 x)

f (x) = 8 x^{3} + 3

3 x - 14

What is the inverse of f(x)=(x-3)^2-8,x>3 ?
The inverse of f(x)=(x-3)^2-8,x>3 is sqrt(x+8)+3,-sqrt(x+8)+3