What is the inverse of f(x)=((3x-10))/(1-3x) ?

The inverse of f(x)=((3x-10))/(1-3x) is -(-10-x)/(3(1+x))

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inverse of f(x)=((3x-10))/(1-3x)

inverse

f (x) = \frac{( 3 x - 10 )}{1 - 3 x}

- \frac{- 10 - x}{3 ( 1 + x )}

Solution steps

y = \frac{3 x - 10}{1 - 3 x}

Replace

x

with

y

x = \frac{3 y - 10}{1 - 3 y}

Solve for

y, x = \frac{3 y - 10}{1 - 3 y}

- \frac{- 10 - x}{3 ( 1 + x )}

\frac{2 ( 3 x - 2 )}{( 3 x - 2 ) + 4}

\frac{4}{x ^{5}}

f (x) = 300 (1 - \frac{2 x}{75})^{2}

f (x) = lo g_{5 x} (6)

y = \frac{3}{2}

What is the inverse of f(x)=((3x-10))/(1-3x) ?
The inverse of f(x)=((3x-10))/(1-3x) is -(-10-x)/(3(1+x))