What is the inverse of f(x)=4x^2,x>= 0 ?

The inverse of f(x)=4x^2,x>= 0 is (sqrt(x))/2 ,-(sqrt(x))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4x^2,x>= 0

inverse

f (x) = 4 x^{2}, x \geq 0

\frac{x}{2}, - \frac{x}{2}

Solution steps

y = 4 x^{2}

Replace

x

with

y

x = 4 y^{2}

Solve for

y, x = 4 y^{2}

\frac{x}{2}, - \frac{x}{2}

f (x) = (x - 4)^{2} + 6

ln (x + 7)

y = \frac{x + 3}{x - 4} + 2

\frac{7372800}{X ^{0.6213712}}

What is the inverse of f(x)=4x^2,x>= 0 ?
The inverse of f(x)=4x^2,x>= 0 is (sqrt(x))/2 ,-(sqrt(x))/2