What is the inverse of f(x)=-(x-1)^2-1 ?

The inverse of f(x)=-(x-1)^2-1 is sqrt(-x-1)+1,-sqrt(-x-1)+1

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inverse of f(x)=-(x-1)^2-1

inverse

f (x) = - (x - 1)^{2} - 1

- x - 1 + 1, - - x - 1 + 1

Solution steps

y = - (x - 1)^{2} - 1

Replace

x

with

y

x = - (y - 1)^{2} - 1

Solve for

y, x = - (y - 1)^{2} - 1

- x - 1 + 1, - - x - 1 + 1

f (x) = e^{\frac{x + 2}{x - 2}}

tan (\frac{3 π}{5})

f (x) = \frac{3 x + 8}{2}

g (x) = - 2 x - 2

\frac{3}{2}

What is the inverse of f(x)=-(x-1)^2-1 ?
The inverse of f(x)=-(x-1)^2-1 is sqrt(-x-1)+1,-sqrt(-x-1)+1