What is the inverse of f(x)=(7x-1)/(2x+8) ?

The inverse of f(x)=(7x-1)/(2x+8) is (-1-8x)/(2x-7)

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inverse of f(x)=(7x-1)/(2x+8)

inverse

f (x) = \frac{7 x - 1}{2 x + 8}

\frac{- 1 - 8 x}{2 x - 7}

Solution steps

y = \frac{7 x - 1}{2 x + 8}

Replace

x

with

y

x = \frac{7 y - 1}{2 y + 8}

Solve for

y, x = \frac{7 y - 1}{2 y + 8}

\frac{- 1 - 8 x}{2 x - 7}

f (x) = \frac{7 x - 1}{2 x + 6}

f (x) = (x + 4)^{2} - 5

f (x) = 4 x - x^{2} - 3

lo g_{3} (4 x - 1) + 1

f (p) = 10 - 2 p^{\frac{1}{2}}

What is the inverse of f(x)=(7x-1)/(2x+8) ?
The inverse of f(x)=(7x-1)/(2x+8) is (-1-8x)/(2x-7)